Đề bài
Viết các phương trình hoá học thực hiện các chuyển đổi hoá học sau:
Tinh bột \(\buildrel {\left( 1 \right)} \over\longrightarrow \) Glucozơ \(\buildrel {\left( 2 \right)} \over\longrightarrow \) rượu etylic \(\buildrel {\left( 3 \right)} \over\longrightarrow \) axit axetic \(\buildrel {\left( 4 \right)} \over\longrightarrow \) etyl axetat \(\buildrel {\left( 5 \right)} \over\longrightarrow \) rượu etylic
Lời giải chi tiết
Các phương trình hóa học:
\(\begin{array}{l}(1)\,{({C_6}{H_{10}}{O_5})_n} + n{H_2}O \to n{C_6}{H_{12}}{O_6}(axit,{t^0})\\\,\,\,\,\,\,\,\,tinh\,bột\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\;\;\;\;glucozo\\(2)\,{C_6}{H_{12}}{O_6} \to 2{C_2}{H_5}OH + 2C{O_2}(men\,rượu)\\\,\,\,\,\,glucozo\,\,\,\,\,\,\,\,\,\,\,\,rượu\,etylic\\(3)\,{C_2}{H_5}OH + {O_2} \to C{H_3}COOH + {H_2}O(men\,giấm)\\\,\,\,\,\,\,rượu\,etylic\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,axit\,axetic\\(4)\,C{H_3}COOH + {C_2}{H_5}OH \mathbin{\lower.3ex\hbox{$\buildrel\textstyle\rightarrow\over{\smash{\leftarrow}\vphantom{_{\vbox to.5ex{\vss}}}}$}} C{H_3}COO{C_2}{H_5} + {H_2}O({H_2}S{O_4}đặc,{t^0})\\\,\,\,\,\,\,\,axit\,axetic\,\,\,\,\,\,\,rượu\,etylic\,\,\,\,\,\,\,etyl\,axetat\\(5)C{H_3}COO{C_2}{H_5} + NaOH \to C{H_3}COONa + {C_2}{H_5}OH\\\,\,\,\,\,\,\,etyl\,axetat\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\;\;\;\;\;\;\;\;\;\;\;rượu\,etylic\end{array}\)
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